2x^2-3x-3=3(3-x)

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Solution for 2x^2-3x-3=3(3-x) equation:


Simplifying
2x2 + -3x + -3 = 3(3 + -1x)

Reorder the terms:
-3 + -3x + 2x2 = 3(3 + -1x)
-3 + -3x + 2x2 = (3 * 3 + -1x * 3)
-3 + -3x + 2x2 = (9 + -3x)

Add '3x' to each side of the equation.
-3 + -3x + 3x + 2x2 = 9 + -3x + 3x

Combine like terms: -3x + 3x = 0
-3 + 0 + 2x2 = 9 + -3x + 3x
-3 + 2x2 = 9 + -3x + 3x

Combine like terms: -3x + 3x = 0
-3 + 2x2 = 9 + 0
-3 + 2x2 = 9

Solving
-3 + 2x2 = 9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 2x2 = 9 + 3

Combine like terms: -3 + 3 = 0
0 + 2x2 = 9 + 3
2x2 = 9 + 3

Combine like terms: 9 + 3 = 12
2x2 = 12

Divide each side by '2'.
x2 = 6

Simplifying
x2 = 6

Take the square root of each side:
x = {-2.449489743, 2.449489743}

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